A 12 V source drives a 3 Ω resistor. What are the current and power dissipated in the resistor?

I = 2 A; P = 24 W

I = 4 A; P = 48 W

Ohm’s law and how power is dissipated in a resistor are being tested here. The current through a resistor follows I = V/R. With a 12 V source and a 3 Ω resistor, the current is 12/3 = 4 A. The power the resistor dissipates as heat is P = VI, so P = 12 V × 4 A = 48 W. You can also confirm this with P = I^2R or P = V^2/R, both giving 48 W. So the current is 4 A and the resistor dissipates 48 W.

I = 6 A; P = 72 W

I = 1 A; P = 12 W

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